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For a short bar magnet ("B-axial")/("B-e...

For a short bar magnet `("B-axial")/("B-equatorial")` is …....

A

`1:2`

B

`1:1`

C

`3:2`

D

`2:1`

Text Solution

Verified by Experts

The correct Answer is:
D
For small bar magnet `B_("axis")= (mu_0)/( 4pi ) (2m)/( x^3) ( x gt gt gt 2l)`
`B_("equator") = (mu_0)/( 4pi ) (m)/( x^3)` (where `x gt gt gt 2l` )
`therefore (B_("axial"))/( B_("equator")) = (2)/(1) = 2:1`
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