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Magnetic dipole moment of current carryi...

Magnetic dipole moment of current carrying circular coil is ...... length of wire of coil.

A

directly proportional

B

directly proportional to square root of

C

inversely proportional to square of

D

directly proportional to square of

Text Solution

Verified by Experts

The correct Answer is:
C

Dipole moment,
`m= NIA = NI (pi r^(2) )`
But length of wire,
`l=2pi r`
`therefore r=(l)/(2pi)`
`therefore r^(2) = (l^2)/(4pi^(2) )`
`therefore m= NI xx pi xx (l^2)/( 4pi^(2) )`
`therefore` In `m= (Nil^(2) )/(4pi ) , (NI)/(4pi)` is constant.
`therefore m prop l^(2) therefore` Option (C) is correct.
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