SI unit of the ratio of Electric flux and Magnetic flux is

Options

A. `m`
B. `ms^(-1)`
C. `ms^(-2)`
D. `ms`

Answer

B

Explanation

`("Electric flux")/("Magnetic flux")= (phi_(E) )/( Phi_(m) ) = (AE)/(AB) = (E )/( B)=(NC^(-1) )/(NA^(-1) m^(-1) ) = (mA)/( C)`
but `C= AS`
`therefore (phi_(E))/( phi_(m) ) = (mA)/( AS) = (m)/(S)`
`therefore` Unit of `(phi_E)/( phi_m)` is the unit of velocity of light `=ms^(-1)`.