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A 250 turn rectangular coil of length 2....

A 250 turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current Of 0.85 `mu_A` and subjected to a magnetic field of strength 0.85 T. Work done for rotating the coil by 180° against the torque is .......

A

`4.55 mu J`

B

`2.3 mu J`

C

`1.15 muJ`

D

`9.1 muJ`

Text Solution

Verified by Experts

The correct Answer is:
D
Work against torque,
`W= mB [ cos theta_(1) - cos theta_(2) ]`
`= mB [ cos 0^(@) - cos 180^(@) ]`
`= mB [1 - (-1) ]`
`= mB [2]`
`= 2mB = 2 NIAB" "[because m= NIA]`
`2 xx 250 xx 85 xx 10^(-6) xx 2.1 xx 10^(-2) xx 1.25 xx 10^(-2) xx 0.85`
`= 94828.125 xx 10^(-10) ~~ 9.5 xx 10^(-6)` J
`= 9.5 mu`J nearer value is in option (D).
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