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Area of a surface is 1256 m^(2). If 25 J...

Area of a surface is `1256 m^(2)`. If `25 Js^(-1)` radiant energy is incident on it at each second and absorbed completely, then find
Magnitude of energy density

Text Solution

Verified by Experts

`rho=(I)/(C )=(0.02)/(3xx10^(-8))=0.00666xx10^(8)`
`~~6.67xx10^(11)Jm^(-3)`
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