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The electric field intensity produced by...

The electric field intensity produced by the radiations coming from 100 W bulb at a 3 m distance is E. The electric field intensity produced by the radiations coming from 50 W bulb at the same distance is:
(a) `(E )/(2)`
(b) `2E`
(c) `(E )/(sqrt(2))`
(d) `sqrt(2)E`

A

`(E )/(2)`

B

2E

C

`(E )/(sqrt(2))`

D

`sqrt(2)E`

Text Solution

Verified by Experts

The correct Answer is:
C
Electric power `P=(E^(2))/(R )`
`therefore P prop E^(2)`
`therefore (P_(2))/(P_(1))=((E_(2))/(E_(1)))^(2)`
`(50)/(100)=((E_(2))/(E ))^(2)`
`((1)/(2))^(1//2)=(E_(2))/(E )`
`therefore E_(2)=(E )/(sqrt(2))`
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