Home
Class 12
PHYSICS
The magnetic field of a beam emerging fr...

The magnetic field of a beam emerging from a filter facing a floodlight is given by `B=12xx10^(-8)sin (1.20xx10^(7)z-3.60xx10^(15)t)` T. What is the average intensity of the beam ?

Text Solution

Verified by Experts

Comparing `B=12xx10^(-8)sin(1.20xx10^(7)z-3.60xx10^(15)t)` with equation `B = B_(0)sin omega t`
`B_(0)=12xx10^(-8)T`
Average intensity of beam.
`I_("average")=(B_(0)^(2))/(2mu_(0))C`
`=(1)/(2)xx((12xx10^(-8))^(2)xx3xx10^(8))/(4xx3.14xx10^(-7))`
`therefore I_("average")=1.71 W//m^(2)`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC WAVES

    KUMAR PRAKASHAN|Exercise SECTION C NCERT EXEMPLAR SOLUTION (Short Answer Type Questions)|9 Videos

  • ELECTROMAGNETIC WAVES

    KUMAR PRAKASHAN|Exercise SECTION C NCERT EXEMPLAR SOLUTION (Long Answer Type Questions)|11 Videos

  • ELECTROMAGNETIC WAVES

    KUMAR PRAKASHAN|Exercise SECTION C NCERT EXEMPLAR SOLUTION (Multiple Choice Questions)|13 Videos

  • ELECTROMAGNETIC INDUCTION

    KUMAR PRAKASHAN|Exercise Section D MCQs (MCQs asked in Competitive Exams )|38 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    KUMAR PRAKASHAN|Exercise Section D ( MCQs asked in Cometitive Exams )|39 Videos

Similar Questions

Explore conceptually related problems

The magnetic field in a plane electromagnetic wave is given by B_(y)=(2xx10^(-7)) T sin (0.5xx10^(3)x+1.5xx10^(11)t) . What is the wavelength and frequency of the wave?

The magnetic field in a plane electromagnetic wave is given by B_(y)=(2xx10^(-7)) T sin (0.5xx10^(3)x+1.5xx10^(11)t) . Write an expression for the electric field.

The electric field in a plane electromagnetic wave propagating along + Y axis is given by E_(y)=30 sin[2xx10^(11)t+300 pi x]hat(j)Vm^(-1) . (a) What is the wavelength and frequency of the wave ? (b) Write an expression for the magnetic field.

For a plane electromagnetic wave propagating along + Y axis, magnetic field is, B_(x)=8xx10^(-6)sin{(3xx10^(8))t-(0.4xx10^(3))y}hat(i)T . Find periodic time, wave no and write equation of corresponding electric field.

Component of electric field of electromagnetic wave is as following : E_(x)=10^(2)sin(pi(9xx10^(14)t-3xx10^(6)z)) , E_(y)=0, E_(z)=0 , then intensity of wave is ….

Electric field associated with a light wave is given E= E_(0) sin [1.57 xx10^(15)x +6.28 xx10^(15) t] V/m. If this light incident on a surface of work function 2.0 eV the stopping potential will be -

The maximum electric field at a distance of 10m from an isotropic point source of light is 3.0 Vm^(-1) . Calculate (a) the maximum value of magnetic field, (b) average intensity of light at that place and (c ) the power of the source. [c=3xx10^(8)ms^(-1), epsilon_(0)=8.854xx10^(-12)C^(2)N^(-1)m^(-2)]

At a certain place, the vertical component of the earth's magnetic field is 0.4 xx 10^(-4) T and horizontal component is 0.3 xx 10^(-4) T. What will be the total intensity of magnetic field of the earth ?