One capacitor with plate area A is being charged up. At a particular instant when charging current is I, what will be displacement current through a planar loop of area `(A)/(2)`, imagined between the plates and parallel to them ?

Options

A. I
B. `(I)/(2)`
C. `(I)/(4)`
D. `(I)/(8)`

Answer

B

Explanation

For a capacitor being charged, conduction current density at any point inside the plate and displacement current density at any point between the plates are always same. Hence,
`(I)/(A)=(i_(d))/(((A)/(2)))`
`therefore I=2i_(d)`
`therefore i_(d)=(I)/(2)`