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Capacitance of capacitor is 2pE. Electri...

Capacitance of capacitor is 2pE. Electric field inside capacitor is changing with the rate of `10^(12)Vs^(-1)`. Then displacement current is …….. A.

A

2

B

3

C

6

D

9

Text Solution

Verified by Experts

The correct Answer is:
A
`I=(d theta)/(dt)` but, putting Q = CV
`=(d)/(dt)[CV]=C.(dV)/(dt)`
`=2xx10^(-12)xx10^(12)`
`therefore I=2A`
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KUMAR PRAKASHAN-ELECTROMAGNETIC WAVES-SECTION D MULTIPLE CHOICE QUESTIONS (MCQs)
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