Relative permeability of medium of refractive index 1.5 and dielectric constant 2 is ……. `TmA^(-1). (mu_(0)=4pi xx10^(-7)TmA^(-1))`

Options

A. (A) `0.45pi xx10^(-7)`
B. (B)`5pi xx 10^(-7)`
C. (C) `5pi xx 10^(-7)`
D. (D) `4.5pi xx10^(-7)`

Answer

D

Explanation

`n=sqrt(mu_(r )K)rArr 1.5 = sqrt((mu_(r )K)`
`therefore (2.25)/(K)=mu_(r )=(mu)/(mu_(0))`
`therefore (mu)/(mu_(0))=(2.25)/(K)`
`rArr mu=(2.25xx4pi xx 10^(-7))/(2)`
`therefore mu=4.5 pi xx 10^(-7)TmA^(-1)`