Radiated energy per second gain by an el...

Radiated energy per second gain by an electric bulb is 25 Joule/second and velocity of electromagnetic wave is c then force gain by the surface per second is ….

`8.33xx10^(-8)J`

`75xx10^(8)N`

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Verified by Experts

The correct Answer is:

`F=(U)/(c )=(25)/(3xx10^(8))=8.33xx10(-8)N`

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