Given magnetic field equation is `vec(B)=3xx10^(-8) sin[omega t-kx + phi] hat(j)` then appropriate equation for electric field `(vec(E ))` will be …….

Options

A. `3xx10^(-9)sin (omega t-kx + phi)hat(k)`
B. `9 sin (omega t - kx + phi)hat(k)`
C. `16xx10^(-9)sin (omega t-kx+phi)hat(k)`
D. `20xx10^(-9)sin(omega t-kx + phi)hat(k)`

Answer

B

Explanation

We know that `(|vec(E )_(0)|)/(|vec(B)_(0)|)=c`
`therefore (E_(0))/(B_(0))=c`
`therefore E_(0)=B_(0)c`
`therefore E_(0)=3xx10^(-8)xx3xx10^(8) " "` [`therefore` From given equation `B_(0)=3xx10^(-8)T`]
`therefore E_(0)=9N//C`
`therefore` Equation of electric field,
`vec(E )=E_(0)sin[omega t-kx + phi)hat(k)`
`therefore vec(E ) = 9 sin [omega t-kx+phi)hat(k)`
Electric field will be in z - direction.