A radiation of energy 'E' falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (c = Velocity of light) :

Options

A. `(E )/(c )`
B. `(2E)/(c )`
C. `(2E)/(c^(2))`
D. `(E )/(c^(2))`

Answer

B

Explanation

Momentum of radiation `p = (E )/(c )`
Momentum transferred to the surface `= p_(f)-p_(i)`

`=(E )/(c )-(-(E )/(c ))`
`= (2E)/(c )`