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The displacement 'x' of a particle movin...

The displacement 'x' of a particle moving along a straight line at time t is given by `x=a_(0)+a_(1)t+a_(2)t^(2)`. The acceleration of the particle is :-

A

`a_0`

B

`2a_(1)`

C

`a_2/2`

D

`2a_2`

Text Solution

Verified by Experts

The correct Answer is:
D
`x = a_(0) + a_(1) t+a_(2)t^(2) ` , Velocity , `v = (dx)/(dt) = 0 + a_(1) + 2a_(2)t`
Acceleration = `a= (dv)/(dt) = 0 + 2a_(2) = 2a_2`
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