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A particle moving along a straight line ...

A particle moving along a straight line has a velocity `v m s^(-1)`, when it cleared a distance of x m. These two are connected by the relation v = `sqrt (49 + x)`. When its velocity is `1 m s^(-1)`, its acceleration is

A

1

B

2

C

7

D

`1/2`

Text Solution

Verified by Experts

The correct Answer is:
D
Given `v = sqrt(49+y)`
Acceleration, `a = (dv)/(dt) = (dv)/(dy) (dy)/(dt) = v (dv)/(dy)`
`=(49+y)^(1//2) xx1/2 (49+y)^(1/2-1) =1/2 ms^(-2)`
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