A body starting from rest moves with constant acceleration. The ratio of distance covered by the body during the 5th sec to that covered in 5 sec is

Options

A. `9/25`
B. `3/25`
C. `25/9`
D. `1/25`

Answer

A

Explanation

Distance covered in `5^(th)` second is
`D_5 = 0 a/2 (2xx5-1) = (9a)/2`
Distance covered in 5 second is
`S_(5) = 0+1/2 xx a xx 5^(2) = (25a)/2`
`:. D_(5)/S_(5) = 9/25`