A juggler keeps n balls going with one hand, so that at any instant, (n - 1) balls are in air and one ball in the hand. If each ball rises to a height of x metres, the time for each ball to stay in his hand is

Options

A. 1 s
B. 1.5 s
C. 2 s
D. 4 s

Answer

A

Explanation

Here , `n = 5 , x = 20 m , g = 10 ms^(-2)`
Time for one ball in hand ,
`=T/(n-1)=(2sqrt((2x)/g))/((n-1))=2/((n-1))sqrt((2x)/g)=2/((5-1))sqrt((2xx29)/10)=1s `