A juggler throws balls into air. He throws one when ever the previous one is at its height point. If he throws n balls each second, the height to which each ball will rise is

Options

A. `(g)/(2n^2)`
B. `(2g)/n^2`
C. `(2g)/n `
D. `(g)/(4n^2)`

Answer

A

Explanation

Time taken by each ball to reach the highest point,
`t = 1/ns`
As the juggler throws the second ball , when the first ball is at its highest point ,so v = 0
Using v = u + at , we get
`0=u+(-g)(1/n)" or " u=(g/n)`
Also `v^(2) =u^(2) +2as`
`:. 0 = (g/2)^(2) +(-2) h " or " h =g/(2n^(2))`