A body is allowed to fall from a height of `100 m`. If the time taken for the first `50 m` is `t_1` and for the remaining `50 m` is `t_2` then :

Options

A. `t_1 = t_2`
B. `t _(1) gt t_(2)`
C. `t _(1) lt t_2`
D. depends upon the mass

Answer

B

Explanation

`s=1/2"gt"_(1)^(2) " or " t_(1)^(2) = (2s)/g`
or `t_(1)^(2) = (50xx2)/g = 100/g " or " t_(1) = 10/sqrtg`
and `100 = 1/2 "gt"^(2) " or " t = (10sqrt2))/sqrtg`
`:. t_(2)=t -t_(1) = 10 /sqrtg (sqrt2 -1) = 0.4t_(1) ` i.e `t_(1) gt t_2`