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The angle made by the vector vecA=2hati+...

The angle made by the vector `vecA=2hati+3hatj` with Y-axis is

A

`tan^(-1) (3/2)`

B

`tan^(-1) (2/3)`

C

`sin^(-1) (2/3)`

D

`cos^(-1) (3/2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Given : `vecA = 2 hati +3 hatj`
Let `theta` be the angle that vector `vecA ` makes with y - axis .
`:. cos theta= ((2hati+3hatj).hatj)/(sqrt(2^2+3^2))=3/sqrt13`
`tan theta = 2/3 " or " theta = tan^(-1) (2/3)`
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