A cricketer can throw a ball to a maximum horizontal distance of 100m. With the same speed how much high above the ground can the cricketer throw the same ball?

Options

A. 50 m
B. 100 m
C. 150 m
D. 200 m

Answer

A

Explanation

Here , `R_("max")=100 m`
(Where is the velocity of the projection of ball )
or ` u^(2) = 100 g " "...(i)`
Using `v^2 -u^2 = 2as`
`:. (0)^(2) - 100 g = 2 (-g) (H) " "` (Using (i))
or H = 50 m