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The maximum range of a projecitle fired ...

The maximum range of a projecitle fired with some initial velocity is found to be 1000 metre The maximum height (H) reached by this projectile is:-

A

250 metre

B

500 metre

C

1000 metre

D

2000 metre

Text Solution

Verified by Experts

The correct Answer is:
A
`R_("max")=u^2/g=100 m ` (R is maximum when `theta = 45^@` )
`H=(u^2sin ^(2) theta)/(2g) =u^2/(2g)xxsin ^(2) 45^(@) =u^2/(4g)=1000 /4 = 250 m`
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