A projectile is given an initial velocity of `(hat(i)+2hat(j))` The Cartesian equation of its path is `(g = 10 ms^(-1))` ( Here , `hati` is the unit vector along horizontal and `hatj` is unit vector vertically upwards)

Options

A. `y = 2x -5x^(2)`
B. `y = x - 5x^(2)`
C. `4y = 2x - 5x^(2)`
D. `y = 2x - 25 x^(2)`

Answer

A

Explanation

`tantheta=(usin theta)/(u cos theta)=2/1`
The desired equation is
`y = x tan theta-(gx^2)/(2u^2cos^2theta)="x"xx2 -(10x^2)/(2(sqrt((1)^2+(2)^2))^2(1/sqrt5)^(2))`
or `y = 2x - 5x^2`