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A projectile is projected with the initi...

A projectile is projected with the initial velocity `(6i + 8j) m//s`. The horizontal range is `(g = 10 m//s^(2))`

A

4.8 m

B

9.6 m

C

19.2 m

D

14.0 m

Text Solution

Verified by Experts

The correct Answer is:
B
Here, ` u cos theta = 6, u sin theta = 8 and g = 10 ms^(-2)`
`:. R=(u^2sin 2theta)/g=(2u^2sin thetacos theta)/g=(2(usintheta)(u cos theta))/g`
`= (2 xx 8 xx 6)/10 = 9.6 m`
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