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Three projectiles A, B and Care projecte...

Three projectiles A, B and Care projected at an angle of `30^@, 45^@, 60^@` respectively. If R_A, R_B and R_C` are ranges of A, B and C respectively then (velocity of projection is same for A, B and C) 

A

`R_(A) = R_(B) =R_(C)`

B

`R_(A) = R_(C) gt R_(B)`

C

`R_(A) lt R_(B) lt R_(C)`

D

`R_(A) = R_(C) lt R_(B)`

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The correct Answer is:
To solve the problem of comparing the ranges of three projectiles A, B, and C projected at angles of \(30^\circ\), \(45^\circ\), and \(60^\circ\) respectively, we can use the formula for the range of a projectile: \[ R = \frac{u^2 \sin(2\theta)}{g} \] where: - \( R \) is the range, - \( u \) is the initial velocity of projection, - \( \theta \) is the angle of projection, - \( g \) is the acceleration due to gravity. Since the initial velocity \( u \) and \( g \) are the same for all three projectiles, we can focus on the term \( \sin(2\theta) \). ### Step 1: Calculate the range for each projectile. 1. **For Projectile A (angle = \(30^\circ\))**: \[ R_A = \frac{u^2 \sin(2 \times 30^\circ)}{g} = \frac{u^2 \sin(60^\circ)}{g} \] \[ \sin(60^\circ) = \frac{\sqrt{3}}{2} \] Therefore, \[ R_A = \frac{u^2 \cdot \frac{\sqrt{3}}{2}}{g} \] 2. **For Projectile B (angle = \(45^\circ\))**: \[ R_B = \frac{u^2 \sin(2 \times 45^\circ)}{g} = \frac{u^2 \sin(90^\circ)}{g} \] \[ \sin(90^\circ) = 1 \] Therefore, \[ R_B = \frac{u^2}{g} \] 3. **For Projectile C (angle = \(60^\circ\))**: \[ R_C = \frac{u^2 \sin(2 \times 60^\circ)}{g} = \frac{u^2 \sin(120^\circ)}{g} \] \[ \sin(120^\circ) = \sin(180^\circ - 60^\circ) = \sin(60^\circ) = \frac{\sqrt{3}}{2} \] Therefore, \[ R_C = \frac{u^2 \cdot \frac{\sqrt{3}}{2}}{g} \] ### Step 2: Compare the ranges. Now we have: - \( R_A = \frac{u^2 \cdot \frac{\sqrt{3}}{2}}{g} \) - \( R_B = \frac{u^2}{g} \) - \( R_C = \frac{u^2 \cdot \frac{\sqrt{3}}{2}}{g} \) From this, we can see that: - \( R_A = R_C \) - \( R_B > R_A \) and \( R_B > R_C \) ### Conclusion: Thus, the ranges can be summarized as: \[ R_A = R_C < R_B \] So, the projectile B, which is launched at \(45^\circ\), has the maximum range, while projectiles A and C, launched at \(30^\circ\) and \(60^\circ\) respectively, have equal ranges. ### Final Result: - \( R_A = R_C \) - \( R_B > R_A \) and \( R_B > R_C \)

To solve the problem of comparing the ranges of three projectiles A, B, and C projected at angles of \(30^\circ\), \(45^\circ\), and \(60^\circ\) respectively, we can use the formula for the range of a projectile: \[ R = \frac{u^2 \sin(2\theta)}{g} \] where: - \( R \) is the range, ...
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