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The kinetic energy of a projectile at th...

The kinetic energy of a projectile at the highest point of its path is found to be `3//4^(th)` of its initial kinetic energy. If the body is projected from the ground, the angle of projection is

A

`30^@`

B

`60^@`

C

`45^@`

D

`120^@`

Text Solution

Verified by Experts

The correct Answer is:
A
According to given problem
`1/2m(u cos theta)^2=3/4xx1/2 "mu"^2`
or `cos^(2) theta =3/4 `
or `cos theta =sqrt3/2 = cos 30^(@) " or " theta = 30^(@)`
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