A particle moves in a circle of radius 5 cm with constant speed and time period `0.2pis`. The acceleration of the particle is

Options

A. `15 m//s^2`
B. `25 m//s^2`
C. `36 m//s^2`
D. `5 m//s^2`

Answer

D

Explanation

Here , Radius , `R = 5 cm = 5 xx 10 ^(-2)m`
Time period , `T = 0.2pis`
Centripetal acceleration ,
`a_c=omega^(2)R=((2pi)/T)^2 R =((2pi)/(0.2pi))^2 (5xx 10^(-2))= 5 m//s^2`
As particle moves with constant speed, therefore its tangential acceleration is zero . So `a_t =0`
The acceleration of the particle is
`a=sqrt(a_c^2+a_(t)^2)=a_c=5m//s^2`
It acts towards the centre of the circle.