A missile is fired for maximum range with an initial velocity of `20m//s`. If `g=10m//s^(2)`, the range of the missile is

Options

A. 40 m
B. 50 m
C. 60 m
D. 20 m

Answer

A

Explanation

Here, `u = 20 m/s , g = 10 m//s^2`
For maximum range , angle of projection is `theta 45^@`
`:.R_(max)=(u^2sin90^@)/g =u^2/g" "(( :.R=(u^2sin 2theta))/g)`
`=((20m//s)2)/((100m//s^(2))=40 m `