The bulk modulus of a metal is `8 xx 10^(9) Nm^(-2)` and its density is 11 g `cm^(-3)`. The density of this metal under a pressure of 20000 N `cm^(-2)` will be (in g `cm^(-3)`)

Explanation

Bulk modulus, `B= -(PV)/(Delta V)`
`:. Delta V= - (PV)/(B)= (2 xx 10^(4) xx 10^(4) V)/(8 xx 10^(9))= -(V)/(40)`
`:.` New volume= `V- (V)/(40) = (39V)/(40)`
Let the new density of metal= `rho. "gram" cm^(-3)`
`:.` Mass of metal `= (39V)/(40) xx rho.`
`or V= xx 11 = (39V xx rho.)/(40) or rho. = (440 "gram")/(39 cm^(3))`