Two liquid A and B are at `32^@C` and `24^@C`. When mixed in equal masses the temperature of the mixture is found to be `28^@C`. Their specific heats are in the ratio of

Options

A. `3:2`
B. `2:3`
C. `1:1`
D. `4:3`

Answer

C

Explanation

When mixed, the heat gained by liquid B is equal to heat lost by liquid A.
The final temperature of the mixture is `28^(@)C`. Heat lost by
`A= m_(A).s_(A) (32-28)`
Heat gained by `B= m_(B).s_(B) (28-24)`
`m_(A)s_(A) (32-28) = m_(B) s_(B) (28-24)`
As `m_(A) = m_(B) rArr s_(A) = s_(B) or s_(A): s_(B) = 1:1`
`rArr` c is correct