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Two wires A and B have the same length and area of cross-section. But Young's modulus of A is two times the Young's modulus of B. Then the ratio of force constant of A to that of B is

A

1

B

2

C

`(1)/(2)`

D

`sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
B

Force constant, `k= (YA)/(L)`
As A and L are same for both the wires, so `k prop Y`
`:. (k_(A))/(k_(B)) = (Y_(A))/(Y_(B)) =2`
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