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The mean distance between the atoms of i...

The mean distance between the atoms of iron is `3xx10^(-10)` m and interatomic fore constant for iron is `7 N//m`. The Young's modulus of elasticity for iron is

A

`2.33 xx 10^(5) N//m^(2)`

B

`23.3 xx 10^(10) N//m^(2)`

C

`2.33 xx 10^(9) N//m^(2)`

D

`2.33 xx 10^(10) N//m`

Text Solution

Verified by Experts

The correct Answer is:
D

Given `r_(0) = 3 xx 10^(-10)m, k= 7N//m`
As `k= Y r_(0)`
`:. Y = (k)/(r_(0)) = (7)/(3 xx 10^(-10)) = 2.33 xx 10^(10) N//m^(2)`
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