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The increase in length of a wire on stre...

The increase in length of a wire on stretching is 0.025%. If its Poisson's ratio is 0.4, then the percentage decrease in diameter is

A

0.0001

B

0.0002

C

0.0003

D

0.0004

Text Solution

Verified by Experts

The correct Answer is:
A
% decrease in diameter
`= (Delta D)/(D) xx 100% = sigma ((Delta l)/(l)) xx 100%` (Using (i))
`= 0.4 xx (0.025)/(100) xx 100% = 0.01%`
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