A flask of volume `10^3` cc is completely filled with mercury at `0^@C` The coefficient of cubical expansion of mercury is `180xx10^(-6)//^(@)C` and heat of glass is `40xx10^(-6)//^(@)C`. If the flask in now placed in boiling water at `100^@C` how much mercury will overflow?

Options

A. 7cc
B. 14 cc
C. 21cc
D. 28cc

Answer

B

Explanation

Increase in the volume of flask `=V gamma_(g) Delta T= 10^(3) xx 40 xx 10^(-6) xx 100=4cc`
Increase in the volumne of mercury `= V_(gamma_(Hg)) Delta T`
`=10^(3) xx 180 xx 10^(-6) xx 100= 18cc`
`:.` Volume of mercury overflow `=18-4=14cc`