A copper block of mass `2.5 kg` is heated in a furnace to a temperature of `500^(@)C` and then placed on a large ice block. What is the maximum amount (approx.) of ice that can melt? (Specific heat copper `= 0.39 J//g^(@)C` heat of fusion of water `= 335 J//g`).

Options

A. 1.5kg
B. 2.5kg
C. 3.5kg
D. 4.5kg

Answer

A

Explanation

Here mass of copper block, `m= 2.5kg= 2500g`
Fall in temperature, `Delta T= 500-0 = 500^(@)C`
Specifici heat of copper, `s= 0.39J g^(-1) K^(-1)`
Latent heat of fusion of ice, `L= 335J g^(-1)`
Let the mass of ice melted be m.
According to the principle of calorimetry
Heat gained by ice = Heat lost by copper
`:. m.L= ms Delta T`
or `m. = (m s Delta T)/(L) = (2500 xx 0.39 xx 500)/(335) = 1455g ~~ 1.5kg`