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Stream at 100^(@)C is passed into 20 g o...

Stream at `100^(@)C` is passed into 20 g of water at `10^(@)C`. When water acquires a temperature of `80^(@)C`, the mass of water present will be [Take specific heat of water `=1 cal g^(-1) .^(@)C^(-1)` and latent heat of steam `=540 cal g^(-1)`]

A

24g

B

31.5g

C

42.5g

D

22.5g

Text Solution

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The correct Answer is:
D
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Steam at 100^(@)C is passed into 20 g of water at 10^(@)C when water acquire a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water = 1 cal g^(-1).^(@) C^(-1) and latent heat of steam = 540 cal g^(-1) ]

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If 2000kg of water is heated from 0^(@) C to 100^(@)C , what will be the corresponding increase in mass of water? Take specific heat of water =1cal. g^(-1).^(@)C^(-1) .

Find the heat energy required to raise the temperature of 5 kg of water at 80^@C to 100^@C . (Specific heat of water is 1 cal g^(-1)""^(@)C^(-1) )

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