A black body is at a temperature of `5760 K`. The energy of radiation emitted by the body at wavelength `250 nm` is `U_(1)` at wavelength `500 nm` is `U_(2)` and that at `1000 nm` is `U_(3)`. Wien's consant, `b = 2.88 xx 10^(6) nmK`. Which of the following is correct?

Options

A. `U_(1) gt U_(2)`
B. `U_(2) gt U_(1)`
C. `U_(1)=0`
D. `U_(3)=0`

Answer

B

Explanation

According to Wein.s displacement law
`lamda_(m) = (b)/(T) = (2.88 xx 10^(6) nm K)/(5760 K) = 500nm`

Clearly from graph `U_(1) lt U_(2) gt U_(3)`