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If the abscissae of points A, B are the ...

If the abscissae of points A, B are the roots
of the equation, `x^(2) + 2ax - b^(2) = 0 ` and ordinates of A, B are roots of `y^(2)+2py- q^(2) = 0`, then find the equation of a circle for which `overline(AB)` is a diameter.

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The correct Answer is:
`x^(2)+y^(2)+2ax+2py-(b^(2)+q^(2))=0`
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