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The internal centre of similitude of the...

The internal centre of similitude of the two circles `x^(2)+y^(2)+6x-2y+1=0, x^(2)+y^(2)-2x-6y+9=0` is

Text Solution

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The correct Answer is:
(i) (2,6) (ii) `(0,5/2)`
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Knowledge Check

  • The centres of similutude of the circles x^(2)+y^(2)-2x-6y+6=0, x^(2)+y^(2)=1 is

    A
    (1/3,1),(-1,-3)
    B
    (1/5,-1) (-1,-5)
    C
    (1/3,1) (1,3)
    D
    (-1/3,-1) (-1,-3)

  • P(-1,-3) is a centre of similitude of for the two circles x^(2)+y^(2)=1 and x^(2)+y^(2)-2x-6y+6=0 . The length of the common tangent through P to the circles is

    A
    2
    B
    3
    C
    4
    D
    5

  • The internal cent re of similitude of two circles (x-2)^(2)+(y-3)^(2)=9,(x+6)^(2)+(y+5)^(2)+9 divides the segement joining their centres in the ratio

    A
    0.085416666666667
    B
    0.25347222222222
    C
    0.084027777777778
    D
    0.042361111111111

    • Similar Questions

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    Find the internal centre of similitude for the circles x^(2) + y^(2) + 6x - 2y + 1 =0 and x^(2) + y^(2) - 2x - 6y + 9 = 0 .

    Find the internal centre of similitude for the circles x ^(2) + y ^(2) + 6x -2y + 1=0 and x^(2) + y ^(2) - 6y + 9=0

    Find the external centre of similitude for the circles x^(2) + y^(2) - 2x - 6y + 9 =0 and x^(2) + y^(2) = 4

    The internal centre of similitude of two circles (x-3)^(2)+(y-2)^(2)=9,(x+5)^(2)+(y+6)^(2)=9 is

    Find the external centre of similitude for the circles x ^(2) + y ^(2) -2x - 6y + 9=0 and x^(2) + y ^(2) =4

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