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The circle with centre (3/2,1/2) and rad...

The circle with centre `(3/2,1/2)` and radius `sqrt(3/2)` is

A

`x^(2)+y^(2)-2x-2y+1=0`

B

`x^(2)+y^(2)+2x+2y+1=0`

C

`x^(2)+y^(2)-3x-y+1=0`

D

`x^(2)+y^(2)+3x+y-1=0`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • The equation of the circle with centre (3, -2) and radius 3 is

    A
    `x^(2)+y^(2)-6x+4y+4=0`
    B
    `x^(2)+y^(2)-4x+6y+9=0`
    C
    `x^(2)+y^(2)+14x+6y-42=0`
    D
    `x^(2)+y^(2)+2x+16y+40=0`

  • The polar equation of the circle with centre (2, (pi)/(2)) and radius 3 units is

    A
    `r^(2) + 4 r cos theta = 5`
    B
    `r^(2) + 4 r sin theta = 5`
    C
    `r^(2) - 4 r sin theta = 5`
    D
    `r^(2) - 4r cos theta = 5`

  • The equatinn of the circle with centre origin and radius 2 is

    A
    `x^(2)+y^(2)-6x+4y+4=0`
    B
    `x^(2)+y^(2)=4`
    C
    `x^(2)+y^(2)-4x+6y-12=0`
    D
    `x^(2)+y^(2)+2x+16y+40=0`

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    In each of the following find the equation of the circle with centre (-a, -b) and radius sqrt(a^(2)-b^(2))

    The cartesian equation of the sphere with centre (2, -1, 3) and radius 5 is

    Let C be the circle with centre (0,0) and radius 3 units. The equation of the locus of the midpoint of the chords of the circle C that substend an angle of 2pi//3 at its centre is

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