Home
Class 12
MATHS
What is the equation to the hyperbola if...

What is the equation to the hyperbola if its latusrectum is `9/2` and eccentricity is `5/4`.

Text Solution

Verified by Experts

The correct Answer is:
1
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • HYPERBOLA

    AAKASH SERIES|Exercise Exercise|6 Videos

  • HYPERBOLA

    AAKASH SERIES|Exercise Examples|10 Videos

  • EXPONENTIAL SERIES

    AAKASH SERIES|Exercise EXERCISE - III|8 Videos

  • INDEFINITE INTEGRALS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|167 Videos

Similar Questions

Explore conceptually related problems

Equation of the hyperbola with latus rectum (22)/(5) and eccentricity 6/5 is

Find the equation of the hyperbola whose foci are (6,4) and (-4,4) and eccentricity is 2.

Knowledge Check

  • The equation of the hyperbola whose foci are ( +- 5,0) and eccentricity 5/3 is

    A
    ` (x^(2))/( 9) -y^( 2)/( 16) =1`
    B
    ` ( x^(2) )/( 4) -( y^(2))/( 16) = 1`
    C
    ` (x^(2) )/( 9) +( y^(2)) /( 6) = 1 `
    D
    ` (x^(2))/( 4) +(y^(2))/( 16) = 1 `

  • The equation to the hyperbola referred to its axes as coordinate axes , whose latus rectum is 4 and eccentricity is 3 is

    A
    `16x^(2) -2y^(2) =1`
    B
    ` 2x^(2) -16y^(2) =1`
    C
    ` 8x^(2) =2y^(2) =1`
    D
    ` 3x^(2) -8y^(2) =1`

  • The equation of the hyperbola with is transverse axis is parallel to y-axis and its centre is (2,-3) the length of transverse axis is 12 and eccentricity 7/6 is

    A
    ` ((y+3)^(2))/( 6) -( ( x+2)^(2))/(3)=1 `
    B
    `((y-3)^(2))/( 36) +((x-2)^(2))/( 13) =1`
    C
    ` ((y+3)^(2))/( 9) -((x-4)^(2))/( 4) =1`
    D
    ` ((y+3)^(2))/( 36) -((x-2)^(2))/(13) =1`

    • Similar Questions

    Explore conceptually related problems

    Equation of the hyperbola with foci (+-2 ,0) and eccentricity 3/2 is

    One focus of a hyperbola is located at the point (1, -3) and the corresponding directrix is the line y = 2. Find the equation of the hyperbola if its eccentricity is (3)/(2)

    The equation of the ellipse whose focus is at (4,0) and whose eccentricity is 4/5 is

    The foci of a hyperbola coincide with the foci of the ellipse (x^(2))/(25) + (y^(2))/(9) = 1 . Find the equation of the hyperbola, if its eccentricity is 2

    The foci of a hyperola coincide with the foci of the ellipse x^(2)/(25)+y^(2)/(9)=1 . Find the equation of the hyperola, if its eccentricity is 2.

    Home
    Profile