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Show that the ar5ea enclosed between the parabolas `y^(2)=4a(x+a)` and `y^(2)=4b(b-x)` where `a gt 0,b gt 0` is `(8)/(3)(a+b)sqrt(ab)` sq units.

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The correct Answer is:
`=(8)/(3)sqrt(ab)(a+b)` sq units
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AAKASH SERIES-AREAS-Exercise-3.2
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  7. Find area enclosed by |y|=1-x^(2).

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  8. Find the area enclosed between y= sqrt(5-x^(2)) and the lines y= |x-1|

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  10. Find the ratio of the curves into which the circle x^(2) + y^(2)= 64 i...

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  12. Find the area of the region bounded by the curves y= x^(2) and y= (2)/...

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  13. The area bounded by the curves y=xe^(x),y=xe^(-x) and line x=1, is

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  14. Find the area of the region bounded by the lines y=|x-1| and y=3-|x|

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  18. Find the area enclosed by y=log(e)(x+e) and x=log(e)((1)/(y)) and the ...

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  19. Let f(x)= "max" {sin x, cos x, (1)/(2)}. Determine the area of the reg...

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  20. Let f(x)=" max "{x^(2),(1-x)^(2),2x(1-x)} where 0le x le 1. Determine ...

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  21. Let A(n) between area bounded by the curve y=(tan x)^(n),n in N and th...

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