Two rings of same radius and mass are placed such that their centres are at a common point and their planes are perpendicular to each other. The moment of inertia of the system about an axis passing through the centre and perpendicular to the plane of one of the rings is (mass the ring `= m`, radius `= r`)

Find the moment of inertia of ring about an axis passing through the centre and perpendicular to its plane.

Two rings of the same radius R and M are placed such that their centres coincide and their planes are perpendicular to each other, the moment of inertia of the system about an axis passing through the diameters of both rings is

Two rings have the same mass (m) and radius (r). They are placed in such away that their centres are at a common point and their planes are perpendicular to each other. What is the moment of inertia of the system about an axis passing through their centre and perpendicular to the plane of one of the ring ?

Find the moment of inertia of a thin circular ring about an axis passing through the centre and perpendicular to the plane of the ring

Calculate the moment of inertia of a ring about in axis passing through centre and perpendicular to its plane.

Two thin uniform circular rings each of radius 10 cm and mass 0.1 kg are arranged such that they have a common centre and their planes are perpendicular to each other. The moment of inertia of this system about an axis passing through their common centre and perpendicular to the plane of one of the rings in kg-m^(2) is

Two rings of the same mass and radius are placed such that their centers are at a common point and their planes are perpendicular to each other . The moment of inertia of the system about an axis passing through the diameter of one of the rings is I . Then moment of inertia of one of the ring of the system about the central axis and perpendicular to its plane would be