The vertices of a `Delta ` ABC are A (-5,-1), B (3,-5) , C (5,2). Show that the area of the `Delta ` ABC is four times the area of the triangle formed by joining the mid-points of the sides of the triangle ABC.

The vertices of a Delta ABC are A(-5,-1) B(3.-5) , C-(5.2).Show that the area of the DeltaABC is four times the area of the triangle formed by joining the mid-points of the sides of the triangle ABC.

prove that the area of a triangle is four times the area of the triangle formed by joining the mid-points of its sides.

prove that the area of a triangle is four times the area of the triangle formed by joining the mid-points of its sides.

If ar( Delta ABC) = 16 cm^(2) then find the area of the triangle formed by joining the mid points of the sides of Delta ABC.

Prove that the area of any triangle is equal to four times the area of the triangle formed by joining the mid points of its sides.

Find the area of the triangle formed by joining the mid -points of the sides of the triangle ABC ,whose vertices are A(0,-1),B(2,1)andC(0,3).

Let A(0,-1),B(0,3)andC(2,1) be three points Let Delta_(1) be the area of the triangle ABC and Delta_(2) be the area of the triangle formed by the mid points of the sides of the triangle whose vertices are A,B and C such that (Delta_(1))/(Delta_(2))=(1)/(x) Find the value of x.

In a triangle ABC,A(5,6),B(-1,4) and centroid is at (2,4). Then area of triangle formed by the mid points of sides of ABC is