Find the dissocation constant `K_(a)` of `HA` (weak monoabsic acid) which is `3.5%` dissociated in an`M//20` solution.

Find the dissociation constant K_(a) of HA (weak monobasic acid) which is 3.5% dissociated in an M//20 solution.

The dissociation constant of a monobasic acid which is 3.5% dissociated in (N)/(20) solution at 20^(@)C is

The dissociation constant of a weak monoprotic acid, which is 0.01 % ioniosed in 1 .00M solution , is

The dissociation constant of a weak monoprotic acid, which is 0.01 % ioniosed in 1 .00M solution , is

What is dissociation constant of a weak acid (K_(a)) .

The dissociation constant (K_(a)) of a certain weak monoprotic acid at 298 K is 1 times 10^(-5) . The % dissociation of this acid in its decimolar aqueous solution at 298 K is

The dissociation constant of a weak monobasic acid is 3.5 xx 10^(-8) . Calculate its degree of dissociation in 0.05 M solution.