ABC is a right angle isosceles triangle with `angleB=90^(@).` If D is a point on AB so that `angle CDB=15^(@)` and if `AD=35` cm then the value of CD is-

ABC is a right angled isosceles triangle with angle B = 90 ^(@) . If D is a point on AB so that angle CDB = 15^(@) and , if AD = 35 Cm, then CD is equal to:

ABC is a right angled isosceles triangles with angle B = 90 ^@ if D is a point on A B so that angle DCB = 15 ^@ and if Ad = 35 cm , then CD=

ABC is a right angled isosceles triangle with /_B=90^(@) If D is a point on AB such that /_CDB=15^(@) and ifAD=35cm then CD is equal to

ABC is a right angled triangle in which angleB=90^(@) and AB=BC . Find angleA and angleC .

in triangle ABC angle C is 90^(@),a=3,b=4 and D is point on AB so that angle BCD=30^(@) then find length of CD

ABC is a right angle triangle having angleB=90^@ . If BD=DC, show that AC^2 = 4AD^2 - 3AB^2

If Delta ABC is an isosceles triangle with angle C=90^(@) and AC=5 cm, then AB is

DeltaABC is an isosceles right angled triangle having angleC=90^(@) . If D is any point on AB, then AD^(2)+BD^(2) is equal to

ABC is a right-angled isoscels triangles of which /_C is a right angle. If D is any point on AB. Then prove that AD^(2) + BD^(2) = 2CD^(2)