The temperature of two bodies A and B are respectively `727^(@)C` and `327^(@)C` . The ratio `H_(A) : H_(B)` of the rates of heat radiated by them is

The temperatures of two bodies A and B are 727^(@)C and 127^(@)C . The ratio of rate of emission of radiations will be

The temperatures of two bodies A and B are 727^(@)C and 127^(@)C . The ratio of rate of emission of radiations will be

Temperature of substances A and B are 727^(@)C and 327^(@)C respectively, then ratio of rate of their radiant energy H_(A):H_(B)= . . . . .

Compare the rate of radiation of metal body at 727 ""^(@)C and 227 ""^(@)C .

Two bodies are at temperature 27^(@) and 927^(@)C . The heat energy radiated by them will be in the ratio:

Two bodies hae temperatures as 227^(@)C and 727^(@)C ratio of heat radiated by them will be

Two black bodies at temperatures 327^@ C and 427^@C are kept in an evacuated chamber at 27^@C . The ratio of their rates of loss of heat are :

The thermal capacities of two bodies A and B are in the ratio 1:4. if the rate of heat loss are equal for these two bodies then the rate of fall of the temperature will be in the ratio