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5g sulphur is present in 100 g of CS(2)....

5g sulphur is present in 100 g of `CS_(2). DeltaT_(b)` of solution 0.954 and `K_(b)` is 4.88. The molecular formula of sulphur is

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3.795 g of sulphur is dissolved in 100g of CS_(2) . This solution boils at 319.81 K. What is the molecular formula of sulphur in solution? The boiling point of CS_(2) is 319.45 kJ (Given that K_(b) for CS_(2) = 2.42 K kg mol^(-1) and atomic mass of S = 32)

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When 2.56 g of sulphur is dissolved in 100 g of CS_(2) , the freezing point of the solution gets lowerd by 0.383 K. Calculate the formula of sulphur (S_(x)) . [Given K_(f) for CS_(2)=3.83 "K kg mol"^(-1) ], [Atomic mass of sulphur=32g mol^(-1) ]

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