A cylindrical copper rod is reformed to twice its original length with no change in volume. The resistance between its ends before the change was R. Now its resistance will be :

A cylindrical rod is reformed to half of its original length keeping volume constant. If its resistance before this change were R, then the resistance after reformation of rod will be

A cylindrical rod is reformed to half of its original length keeping volume constant. If its resistance before this change were R, then the resistance after reformation of rod will be

A resistance R is stretched to four times its length. Its new resistance will be

If a wire of resistance R is stretched to twice its original length, the new resistance of the wire will be:

A resistance 10 Omega is stretched to twice its original length . The resistance of the stretched wire is

A metal resistance R is stretched to double its length. Its new resistance will be ………….. .

A wire of resistance R is stretched to thrice its original length keeping the volume constant. Calculate its new resistance.