There is a set of four tuning forks , one with the lowest frequency vibrating at `550 Hz`. By using any two tuning forks at a time , the following beat frequencies are heard : `1 , 2, 3, 5 , 7 , 8`. The possible frequencies of the other three forks are

You are given four tuning forks, the lowest frequency of the forks is 300 Hz . By striking two tuning forks at a time any of 1,2,3,5,7 & 8 Hz beat frequencies are heard. The possible frequencies of the other three forks are -

You are given four tuning forks, the lowest frequency of the fork is 300Hz. By striking two tuning forks at a time any of 1, 2, 3, 5, 7 & 8 Hz beat frequencies are heard. The possible frequencies of the other three forks – (1) 301, 302 & 307 (2) 301, 303 & 308 (3) 300, 304 & 307 (4) 305, 307 & 308

A tuning fork gives 5 beats with another tuning fork of frequency 100 Hz . When the first tuning fork is loaded with wax, then the number of beats remains unchanged, then what will be the frequency of the first tuning fork

The frequency of tuning fork is 256 Hz. It will not resonate with a fork of frequency

A set of 28 tuning forks is arranged in a series of decreasing frequencies.Each fork girves 4 beats per second with the preceding one and the frequencies of the first forks is an octave of the last.The frequency of the first fork in Hz is

Ten tuning forks are arranged in increasing order of frequency is such a way that any two nearest tuning forks produce 4 beast//sec . The highest freqeuncy is twice of the lowest. Possible highest and the lowest frequencies are